0=27x-0.83x^2

Solution for 0=27x-0.83x^2 equation:

0=27x-0.83x^2

We move all terms to the left:

0-(27x-0.83x^2)=0

We add all the numbers together, and all the variables

-(27x-0.83x^2)=0

We get rid of parentheses

0.83x^2-27x=0

a = 0.83; b = -27; c = 0;
Δ = b2-4ac
Δ = -272-4·0.83·0
Δ = 729
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{729}=27$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-27)-27}{2*0.83}=\frac{0}{1.66}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-27)+27}{2*0.83}=\frac{54}{1.66}
=32+0.88/1.66
$